5(3-2x)=7(4x-1)-2(3x+5)

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Solution for 5(3-2x)=7(4x-1)-2(3x+5) equation: 



5(3-2x)=7(4x-1)-2(3x+5)

We move all terms to the left:

5(3-2x)-(7(4x-1)-2(3x+5))=0

We add all the numbers together, and all the variables

5(-2x+3)-(7(4x-1)-2(3x+5))=0

We multiply parentheses

-10x-(7(4x-1)-2(3x+5))+15=0



We calculate terms in parentheses: -(7(4x-1)-2(3x+5)), so:

7(4x-1)-2(3x+5)

We multiply parentheses

28x-6x-7-10

We add all the numbers together, and all the variables

22x-17

Back to the equation:

-(22x-17)



We get rid of parentheses

-10x-22x+17+15=0

We add all the numbers together, and all the variables

-32x+32=0

We move all terms containing x to the left, all other terms to the right

-32x=-32

x=-32/-32

x=1

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