(1/6)*x-(3/4)=(1/4)*x

Solution for (1/6)*x-(3/4)=(1/4)*x equation:

(1/6)*x-(3/4)=(1/4)*x

We move all terms to the left:

(1/6)*x-(3/4)-((1/4)*x)=0


Domain of the equation: 6)*x!=0

x!=0/1

x!=0

x∈R



Domain of the equation: 4)*x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/6)*x-((+1/4)*x)-(+3/4)=0

We multiply parentheses

x^2-((+1/4)*x)-(+3/4)=0

We get rid of parentheses

x^2-((+1/4)*x)-3/4=0

We calculate fractions


x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$