5(3+x)-7x=40+3x

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Solution for 5(3+x)-7x=40+3x equation: 



5(3+x)-7x=40+3x

We move all terms to the left:

5(3+x)-7x-(40+3x)=0

We add all the numbers together, and all the variables

5(x+3)-7x-(3x+40)=0

We add all the numbers together, and all the variables

-7x+5(x+3)-(3x+40)=0

We multiply parentheses

-7x+5x-(3x+40)+15=0

We get rid of parentheses

-7x+5x-3x-40+15=0

We add all the numbers together, and all the variables

-5x-25=0

We move all terms containing x to the left, all other terms to the right

-5x=25

x=25/-5

x=-5

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