-4(2x+1)+5x+1=4(x-3)+6

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Solution for -4(2x+1)+5x+1=4(x-3)+6 equation: 



-4(2x+1)+5x+1=4(x-3)+6

We move all terms to the left:

-4(2x+1)+5x+1-(4(x-3)+6)=0

We add all the numbers together, and all the variables

5x-4(2x+1)-(4(x-3)+6)+1=0

We multiply parentheses

5x-8x-(4(x-3)+6)-4+1=0



We calculate terms in parentheses: -(4(x-3)+6), so:

4(x-3)+6

We multiply parentheses

4x-12+6

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We add all the numbers together, and all the variables

-3x-(4x-6)-3=0

We get rid of parentheses

-3x-4x+6-3=0

We add all the numbers together, and all the variables

-7x+3=0

We move all terms containing x to the left, all other terms to the right

-7x=-3

x=-3/-7

x=3/7

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