5(3+4v)=13(1-v)

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Solution for 5(3+4v)=13(1-v) equation:



5(3+4v)=13(1-v)
We move all terms to the left:
5(3+4v)-(13(1-v))=0
We add all the numbers together, and all the variables
5(4v+3)-(13(-1v+1))=0
We multiply parentheses
20v-(13(-1v+1))+15=0
We calculate terms in parentheses: -(13(-1v+1)), so:
13(-1v+1)
We multiply parentheses
-13v+13
Back to the equation:
-(-13v+13)
We get rid of parentheses
20v+13v-13+15=0
We add all the numbers together, and all the variables
33v+2=0
We move all terms containing v to the left, all other terms to the right
33v=-2
v=-2/33
v=-2/33

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