3(1+3n)+4=19+5n

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Solution for 3(1+3n)+4=19+5n equation: 



3(1+3n)+4=19+5n

We move all terms to the left:

3(1+3n)+4-(19+5n)=0

We add all the numbers together, and all the variables

3(3n+1)-(5n+19)+4=0

We multiply parentheses

9n-(5n+19)+3+4=0

We get rid of parentheses

9n-5n-19+3+4=0

We add all the numbers together, and all the variables

4n-12=0

We move all terms containing n to the left, all other terms to the right

4n=12

n=12/4

n=3

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