5(2z-3)=6(3z+2)-35

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Solution for 5(2z-3)=6(3z+2)-35 equation: 



5(2z-3)=6(3z+2)-35

We move all terms to the left:

5(2z-3)-(6(3z+2)-35)=0

We multiply parentheses

10z-(6(3z+2)-35)-15=0



We calculate terms in parentheses: -(6(3z+2)-35), so:

6(3z+2)-35

We multiply parentheses

18z+12-35

We add all the numbers together, and all the variables

18z-23

Back to the equation:

-(18z-23)



We get rid of parentheses

10z-18z+23-15=0

We add all the numbers together, and all the variables

-8z+8=0

We move all terms containing z to the left, all other terms to the right

-8z=-8

z=-8/-8

z=1

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