7(2x+3)=91-4(3x-2)

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Solution for 7(2x+3)=91-4(3x-2) equation: 



7(2x+3)=91-4(3x-2)

We move all terms to the left:

7(2x+3)-(91-4(3x-2))=0

We multiply parentheses

14x-(91-4(3x-2))+21=0



We calculate terms in parentheses: -(91-4(3x-2)), so:

91-4(3x-2)

determiningTheFunctionDomain
-4(3x-2)+91

We multiply parentheses

-12x+8+91

We add all the numbers together, and all the variables

-12x+99

Back to the equation:

-(-12x+99)



We get rid of parentheses

14x+12x-99+21=0

We add all the numbers together, and all the variables

26x-78=0

We move all terms containing x to the left, all other terms to the right

26x=78

x=78/26

x=3

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