5(2z-1)-4(z+1)=2(z+1)

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Solution for 5(2z-1)-4(z+1)=2(z+1) equation:



5(2z-1)-4(z+1)=2(z+1)
We move all terms to the left:
5(2z-1)-4(z+1)-(2(z+1))=0
We multiply parentheses
10z-4z-(2(z+1))-5-4=0
We calculate terms in parentheses: -(2(z+1)), so:
2(z+1)
We multiply parentheses
2z+2
Back to the equation:
-(2z+2)
We add all the numbers together, and all the variables
6z-(2z+2)-9=0
We get rid of parentheses
6z-2z-2-9=0
We add all the numbers together, and all the variables
4z-11=0
We move all terms containing z to the left, all other terms to the right
4z=11
z=11/4
z=2+3/4

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