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1/2x-1/3=1/6x+1
We move all terms to the left:
1/2x-1/3-(1/6x+1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 6x+1)!=0We get rid of parentheses
x∈R
1/2x-1/6x-1-1/3=0
We calculate fractions
(-72x^2)/108x^2+54x/108x^2+(-18x)/108x^2-1=0
We multiply all the terms by the denominator
(-72x^2)+54x+(-18x)-1*108x^2=0
Wy multiply elements
(-72x^2)-108x^2+54x+(-18x)=0
We get rid of parentheses
-72x^2-108x^2+54x-18x=0
We add all the numbers together, and all the variables
-180x^2+36x=0
a = -180; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·(-180)·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*-180}=\frac{-72}{-360} =1/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*-180}=\frac{0}{-360} =0 $
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