5(2z+4)=8(z-3)

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Solution for 5(2z+4)=8(z-3) equation: 



5(2z+4)=8(z-3)

We move all terms to the left:

5(2z+4)-(8(z-3))=0

We multiply parentheses

10z-(8(z-3))+20=0



We calculate terms in parentheses: -(8(z-3)), so:

8(z-3)

We multiply parentheses

8z-24

Back to the equation:

-(8z-24)



We get rid of parentheses

10z-8z+24+20=0

We add all the numbers together, and all the variables

2z+44=0

We move all terms containing z to the left, all other terms to the right

2z=-44

z=-44/2

z=-22

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