5(2y-2)=9(y+3)

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Solution for 5(2y-2)=9(y+3) equation: 



5(2y-2)=9(y+3)

We move all terms to the left:

5(2y-2)-(9(y+3))=0

We multiply parentheses

10y-(9(y+3))-10=0



We calculate terms in parentheses: -(9(y+3)), so:

9(y+3)

We multiply parentheses

9y+27

Back to the equation:

-(9y+27)



We get rid of parentheses

10y-9y-27-10=0

We add all the numbers together, and all the variables

y-37=0

We move all terms containing y to the left, all other terms to the right

y=37

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