(3p+1)=6(p-8)-(p+2)

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Solution for (3p+1)=6(p-8)-(p+2) equation: 



(3p+1)=6(p-8)-(p+2)

We move all terms to the left:

(3p+1)-(6(p-8)-(p+2))=0

We get rid of parentheses

3p-(6(p-8)-(p+2))+1=0



We calculate terms in parentheses: -(6(p-8)-(p+2)), so:

6(p-8)-(p+2)

We multiply parentheses

6p-(p+2)-48

We get rid of parentheses

6p-p-2-48

We add all the numbers together, and all the variables

5p-50

Back to the equation:

-(5p-50)



We get rid of parentheses

3p-5p+50+1=0

We add all the numbers together, and all the variables

-2p+51=0

We move all terms containing p to the left, all other terms to the right

-2p=-51

p=-51/-2

p=25+1/2

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