5(2y-1)=12y-5-2y

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Solution for 5(2y-1)=12y-5-2y equation: 



5(2y-1)=12y-5-2y

We move all terms to the left:

5(2y-1)-(12y-5-2y)=0

We add all the numbers together, and all the variables

5(2y-1)-(10y-5)=0

We multiply parentheses

10y-(10y-5)-5=0

We get rid of parentheses

10y-10y+5-5=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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