V(a)=(8-2a)(6-2a)

Solution for V(a)=(8-2a)(6-2a) equation:

(V)=(8-2V)(6-2V)

We move all terms to the left:

(V)-((8-2V)(6-2V))=0

We add all the numbers together, and all the variables

V-((-2V+8)(-2V+6))=0

We multiply parentheses ..

-((+4V^2-12V-16V+48))+V=0


We calculate terms in parentheses: -((+4V^2-12V-16V+48)), so:

(+4V^2-12V-16V+48)

We get rid of parentheses

4V^2-12V-16V+48

We add all the numbers together, and all the variables

4V^2-28V+48

Back to the equation:

-(4V^2-28V+48)


We add all the numbers together, and all the variables

V-(4V^2-28V+48)=0

We get rid of parentheses

-4V^2+V+28V-48=0

We add all the numbers together, and all the variables

-4V^2+29V-48=0

a = -4; b = 29; c = -48;
Δ = b2-4ac
Δ = 292-4·(-4)·(-48)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$V_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{73}}{2*-4}=\frac{-29-\sqrt{73}}{-8}
$
$V_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{73}}{2*-4}=\frac{-29+\sqrt{73}}{-8}
$