5(2x-7)+2=-2(7-x)+10

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Solution for 5(2x-7)+2=-2(7-x)+10 equation: 



5(2x-7)+2=-2(7-x)+10

We move all terms to the left:

5(2x-7)+2-(-2(7-x)+10)=0

We add all the numbers together, and all the variables

5(2x-7)-(-2(-1x+7)+10)+2=0

We multiply parentheses

10x-(-2(-1x+7)+10)-35+2=0



We calculate terms in parentheses: -(-2(-1x+7)+10), so:

-2(-1x+7)+10

We multiply parentheses

2x-14+10

We add all the numbers together, and all the variables

2x-4

Back to the equation:

-(2x-4)



We add all the numbers together, and all the variables

10x-(2x-4)-33=0

We get rid of parentheses

10x-2x+4-33=0

We add all the numbers together, and all the variables

8x-29=0

We move all terms containing x to the left, all other terms to the right

8x=29

x=29/8

x=3+5/8

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