11(4c+4)-4c=15c+15

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Solution for 11(4c+4)-4c=15c+15 equation: 



11(4c+4)-4c=15c+15

We move all terms to the left:

11(4c+4)-4c-(15c+15)=0

We add all the numbers together, and all the variables

-4c+11(4c+4)-(15c+15)=0

We multiply parentheses

-4c+44c-(15c+15)+44=0

We get rid of parentheses

-4c+44c-15c-15+44=0

We add all the numbers together, and all the variables

25c+29=0

We move all terms containing c to the left, all other terms to the right

25c=-29

c=-29/25

c=-1+4/25

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