1+2b+3=-(1-b)-(b-1)

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Solution for 1+2b+3=-(1-b)-(b-1) equation: 



1+2b+3=-(1-b)-(b-1)

We move all terms to the left:

1+2b+3-(-(1-b)-(b-1))=0

We add all the numbers together, and all the variables

2b-(-(-1b+1)-(b-1))+1+3=0

We add all the numbers together, and all the variables

2b-(-(-1b+1)-(b-1))+4=0



We calculate terms in parentheses: -(-(-1b+1)-(b-1)), so:

-(-1b+1)-(b-1)

We get rid of parentheses

1b-b-1+1

We add all the numbers together, and all the variables



Back to the equation:

-()



We add all the numbers together, and all the variables

2b=0

b=0/2

b=0

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