5(2x-3)=8-(x+2)

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Solution for 5(2x-3)=8-(x+2) equation: 



5(2x-3)=8-(x+2)

We move all terms to the left:

5(2x-3)-(8-(x+2))=0

We multiply parentheses

10x-(8-(x+2))-15=0



We calculate terms in parentheses: -(8-(x+2)), so:

8-(x+2)

determiningTheFunctionDomain
-(x+2)+8

We get rid of parentheses

-x-2+8

We add all the numbers together, and all the variables

-1x+6

Back to the equation:

-(-1x+6)



We get rid of parentheses

10x+1x-6-15=0

We add all the numbers together, and all the variables

11x-21=0

We move all terms containing x to the left, all other terms to the right

11x=21

x=21/11

x=1+10/11

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