4(b-3)+15=3b

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Solution for 4(b-3)+15=3b equation: 



4(b-3)+15=3b

We move all terms to the left:

4(b-3)+15-(3b)=0

We add all the numbers together, and all the variables

-3b+4(b-3)+15=0

We multiply parentheses

-3b+4b-12+15=0

We add all the numbers together, and all the variables

b+3=0

We move all terms containing b to the left, all other terms to the right

b=-3

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