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5(2x-3)+x-4=-2(3x+4)-10x+3
We move all terms to the left:
5(2x-3)+x-4-(-2(3x+4)-10x+3)=0
We add all the numbers together, and all the variables
x+5(2x-3)-(-2(3x+4)-10x+3)-4=0
We multiply parentheses
x+10x-(-2(3x+4)-10x+3)-15-4=0
We calculate terms in parentheses: -(-2(3x+4)-10x+3), so:We add all the numbers together, and all the variables
-2(3x+4)-10x+3
We add all the numbers together, and all the variables
-10x-2(3x+4)+3
We multiply parentheses
-10x-6x-8+3
We add all the numbers together, and all the variables
-16x-5
Back to the equation:
-(-16x-5)
11x-(-16x-5)-19=0
We get rid of parentheses
11x+16x+5-19=0
We add all the numbers together, and all the variables
27x-14=0
We move all terms containing x to the left, all other terms to the right
27x=14
x=14/27
x=14/27
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