3(z-2)-z=4z-20

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Solution for 3(z-2)-z=4z-20 equation: 



3(z-2)-z=4z-20

We move all terms to the left:

3(z-2)-z-(4z-20)=0

We add all the numbers together, and all the variables

-1z+3(z-2)-(4z-20)=0

We multiply parentheses

-1z+3z-(4z-20)-6=0

We get rid of parentheses

-1z+3z-4z+20-6=0

We add all the numbers together, and all the variables

-2z+14=0

We move all terms containing z to the left, all other terms to the right

-2z=-14

z=-14/-2

z=+7

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