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5(2x-2)=4(3x-3)
We move all terms to the left:
5(2x-2)-(4(3x-3))=0
We multiply parentheses
10x-(4(3x-3))-10=0
We calculate terms in parentheses: -(4(3x-3)), so:We get rid of parentheses
4(3x-3)
We multiply parentheses
12x-12
Back to the equation:
-(12x-12)
10x-12x+12-10=0
We add all the numbers together, and all the variables
-2x+2=0
We move all terms containing x to the left, all other terms to the right
-2x=-2
x=-2/-2
x=1
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