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5(2x-12)=7(x+15)
We move all terms to the left:
5(2x-12)-(7(x+15))=0
We multiply parentheses
10x-(7(x+15))-60=0
We calculate terms in parentheses: -(7(x+15)), so:We get rid of parentheses
7(x+15)
We multiply parentheses
7x+105
Back to the equation:
-(7x+105)
10x-7x-105-60=0
We add all the numbers together, and all the variables
3x-165=0
We move all terms containing x to the left, all other terms to the right
3x=165
x=165/3
x=55
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