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16x^2+44x+18=0
a = 16; b = 44; c = +18;
Δ = b2-4ac
Δ = 442-4·16·18
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-28}{2*16}=\frac{-72}{32} =-2+1/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+28}{2*16}=\frac{-16}{32} =-1/2 $
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