X2-7x+12=(X-4)(X-)

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Solution for X2-7x+12=(X-4)(X-) equation:



X2-7X+12=(X-4)(X-)
We move all terms to the left:
X2-7X+12-((X-4)(X-))=0
We add all the numbers together, and all the variables
X2-7X-((X-4)(+X))+12=0
We add all the numbers together, and all the variables
X^2-7X-((X-4)(+X))+12=0
We multiply parentheses ..
X^2-((+X^2-4X))-7X+12=0
We calculate terms in parentheses: -((+X^2-4X)), so:
(+X^2-4X)
We get rid of parentheses
X^2-4X
Back to the equation:
-(X^2-4X)
We add all the numbers together, and all the variables
X^2-7X-(X^2-4X)+12=0
We get rid of parentheses
X^2-X^2-7X+4X+12=0
We add all the numbers together, and all the variables
-3X+12=0
We move all terms containing X to the left, all other terms to the right
-3X=-12
X=-12/-3
X=+4

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