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5(2x-1)=2(3x+1)-3
We move all terms to the left:
5(2x-1)-(2(3x+1)-3)=0
We multiply parentheses
10x-(2(3x+1)-3)-5=0
We calculate terms in parentheses: -(2(3x+1)-3), so:We get rid of parentheses
2(3x+1)-3
We multiply parentheses
6x+2-3
We add all the numbers together, and all the variables
6x-1
Back to the equation:
-(6x-1)
10x-6x+1-5=0
We add all the numbers together, and all the variables
4x-4=0
We move all terms containing x to the left, all other terms to the right
4x=4
x=4/4
x=1
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