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1/9x=3x/3*81x
We move all terms to the left:
1/9x-(3x/3*81x)=0
Domain of the equation: 9x!=0
x!=0/9
x!=0
x∈R
Domain of the equation: 3*81x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
1/9x-(+3x/3*81x)=0
We get rid of parentheses
1/9x-3x/3*81x=0
We calculate fractions
(-27x^2)/17496x^2+1944x/17496x^2=0
We multiply all the terms by the denominator
(-27x^2)+1944x=0
We get rid of parentheses
-27x^2+1944x=0
a = -27; b = 1944; c = 0;
Δ = b2-4ac
Δ = 19442-4·(-27)·0
Δ = 3779136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3779136}=1944$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1944)-1944}{2*-27}=\frac{-3888}{-54} =+72 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1944)+1944}{2*-27}=\frac{0}{-54} =0 $
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