-6(-4u+1)-6u=3(u-4)-6

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Solution for -6(-4u+1)-6u=3(u-4)-6 equation: 



-6(-4u+1)-6u=3(u-4)-6

We move all terms to the left:

-6(-4u+1)-6u-(3(u-4)-6)=0

We add all the numbers together, and all the variables

-6u-6(-4u+1)-(3(u-4)-6)=0

We multiply parentheses

-6u+24u-(3(u-4)-6)-6=0



We calculate terms in parentheses: -(3(u-4)-6), so:

3(u-4)-6

We multiply parentheses

3u-12-6

We add all the numbers together, and all the variables

3u-18

Back to the equation:

-(3u-18)



We add all the numbers together, and all the variables

18u-(3u-18)-6=0

We get rid of parentheses

18u-3u+18-6=0

We add all the numbers together, and all the variables

15u+12=0

We move all terms containing u to the left, all other terms to the right

15u=-12

u=-12/15

u=-4/5

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