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5(2x-1)-2(3x+3)=6+7(x+4)
We move all terms to the left:
5(2x-1)-2(3x+3)-(6+7(x+4))=0
We multiply parentheses
10x-6x-(6+7(x+4))-5-6=0
We calculate terms in parentheses: -(6+7(x+4)), so:We add all the numbers together, and all the variables
6+7(x+4)
determiningTheFunctionDomain 7(x+4)+6
We multiply parentheses
7x+28+6
We add all the numbers together, and all the variables
7x+34
Back to the equation:
-(7x+34)
4x-(7x+34)-11=0
We get rid of parentheses
4x-7x-34-11=0
We add all the numbers together, and all the variables
-3x-45=0
We move all terms containing x to the left, all other terms to the right
-3x=45
x=45/-3
x=-15
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