13=-2(y-4)+3

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Solution for 13=-2(y-4)+3 equation: 



13=-2(y-4)+3

We move all terms to the left:

13-(-2(y-4)+3)=0



We calculate terms in parentheses: -(-2(y-4)+3), so:

-2(y-4)+3

We multiply parentheses

-2y+8+3

We add all the numbers together, and all the variables

-2y+11

Back to the equation:

-(-2y+11)



We get rid of parentheses

2y-11+13=0

We add all the numbers together, and all the variables

2y+2=0

We move all terms containing y to the left, all other terms to the right

2y=-2

y=-2/2

y=-1

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