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5(2x-1)(6x-7)=0
We multiply parentheses ..
5(+12x^2-14x-6x+7)=0
We multiply parentheses
60x^2-70x-30x+35=0
We add all the numbers together, and all the variables
60x^2-100x+35=0
a = 60; b = -100; c = +35;
Δ = b2-4ac
Δ = -1002-4·60·35
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1600}=40$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-40}{2*60}=\frac{60}{120} =1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+40}{2*60}=\frac{140}{120} =1+1/6 $
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