3(j+4)=9(-2+j)

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Solution for 3(j+4)=9(-2+j) equation: 



3(j+4)=9(-2+j)

We move all terms to the left:

3(j+4)-(9(-2+j))=0

We add all the numbers together, and all the variables

3(j+4)-(9(j-2))=0

We multiply parentheses

3j-(9(j-2))+12=0



We calculate terms in parentheses: -(9(j-2)), so:

9(j-2)

We multiply parentheses

9j-18

Back to the equation:

-(9j-18)



We get rid of parentheses

3j-9j+18+12=0

We add all the numbers together, and all the variables

-6j+30=0

We move all terms containing j to the left, all other terms to the right

-6j=-30

j=-30/-6

j=+5

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