12-5(3c+2)=17

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Solution for 12-5(3c+2)=17 equation: 



12-5(3c+2)=17

We move all terms to the left:

12-5(3c+2)-(17)=0

We add all the numbers together, and all the variables

-5(3c+2)-5=0

We multiply parentheses

-15c-10-5=0

We add all the numbers together, and all the variables

-15c-15=0

We move all terms containing c to the left, all other terms to the right

-15c=15

c=15/-15

c=-1

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