5(2x+4)-3x=7x-(x-4)

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Solution for 5(2x+4)-3x=7x-(x-4) equation: 



5(2x+4)-3x=7x-(x-4)

We move all terms to the left:

5(2x+4)-3x-(7x-(x-4))=0

We add all the numbers together, and all the variables

-3x+5(2x+4)-(7x-(x-4))=0

We multiply parentheses

-3x+10x-(7x-(x-4))+20=0



We calculate terms in parentheses: -(7x-(x-4)), so:

7x-(x-4)

We get rid of parentheses

7x-x+4

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

7x-(6x+4)+20=0

We get rid of parentheses

7x-6x-4+20=0

We add all the numbers together, and all the variables

x+16=0

We move all terms containing x to the left, all other terms to the right

x=-16

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