5(2x+4)+2(6x-5)=3(7x-1)

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Solution for 5(2x+4)+2(6x-5)=3(7x-1) equation: 



5(2x+4)+2(6x-5)=3(7x-1)

We move all terms to the left:

5(2x+4)+2(6x-5)-(3(7x-1))=0

We multiply parentheses

10x+12x-(3(7x-1))+20-10=0



We calculate terms in parentheses: -(3(7x-1)), so:

3(7x-1)

We multiply parentheses

21x-3

Back to the equation:

-(21x-3)



We add all the numbers together, and all the variables

22x-(21x-3)+10=0

We get rid of parentheses

22x-21x+3+10=0

We add all the numbers together, and all the variables

x+13=0

We move all terms containing x to the left, all other terms to the right

x=-13

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