6(2z+2)=4(-2z-2)

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Solution for 6(2z+2)=4(-2z-2) equation: 



6(2z+2)=4(-2z-2)

We move all terms to the left:

6(2z+2)-(4(-2z-2))=0

We multiply parentheses

12z-(4(-2z-2))+12=0



We calculate terms in parentheses: -(4(-2z-2)), so:

4(-2z-2)

We multiply parentheses

-8z-8

Back to the equation:

-(-8z-8)



We get rid of parentheses

12z+8z+8+12=0

We add all the numbers together, and all the variables

20z+20=0

We move all terms containing z to the left, all other terms to the right

20z=-20

z=-20/20

z=-1

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