5(2x+3)=x+3(x+1)

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Solution for 5(2x+3)=x+3(x+1) equation: 



5(2x+3)=x+3(x+1)

We move all terms to the left:

5(2x+3)-(x+3(x+1))=0

We multiply parentheses

10x-(x+3(x+1))+15=0



We calculate terms in parentheses: -(x+3(x+1)), so:

x+3(x+1)

We multiply parentheses

x+3x+3

We add all the numbers together, and all the variables

4x+3

Back to the equation:

-(4x+3)



We get rid of parentheses

10x-4x-3+15=0

We add all the numbers together, and all the variables

6x+12=0

We move all terms containing x to the left, all other terms to the right

6x=-12

x=-12/6

x=-2

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