3/2x+12-2.5x=2x+30-6

Solution for 3/2x+12-2.5x=2x+30-6 equation:

3/2x+12-2.5x=2x+30-6

We move all terms to the left:

3/2x+12-2.5x-(2x+30-6)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

3/2x-2.5x-(2x+24)+12=0

We add all the numbers together, and all the variables

-2.5x+3/2x-(2x+24)+12=0

We get rid of parentheses

-2.5x+3/2x-2x-24+12=0

We multiply all the terms by the denominator


-(2.5x)*2x-2x*2x-24*2x+12*2x+3=0

We add all the numbers together, and all the variables

-(+2.5x)*2x-2x*2x-24*2x+12*2x+3=0

We multiply parentheses

-4x^2-2x*2x-24*2x+12*2x+3=0

Wy multiply elements

-4x^2-4x^2-48x+24x+3=0

We add all the numbers together, and all the variables

-8x^2-24x+3=0

a = -8; b = -24; c = +3;
Δ = b2-4ac
Δ = -242-4·(-8)·3
Δ = 672
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{672}=\sqrt{16*42}=\sqrt{16}*\sqrt{42}=4\sqrt{42}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-4\sqrt{42}}{2*-8}=\frac{24-4\sqrt{42}}{-16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+4\sqrt{42}}{2*-8}=\frac{24+4\sqrt{42}}{-16}
$