6(3x+3)=2(2x-5)

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Solution for 6(3x+3)=2(2x-5) equation: 



6(3x+3)=2(2x-5)

We move all terms to the left:

6(3x+3)-(2(2x-5))=0

We multiply parentheses

18x-(2(2x-5))+18=0



We calculate terms in parentheses: -(2(2x-5)), so:

2(2x-5)

We multiply parentheses

4x-10

Back to the equation:

-(4x-10)



We get rid of parentheses

18x-4x+10+18=0

We add all the numbers together, and all the variables

14x+28=0

We move all terms containing x to the left, all other terms to the right

14x=-28

x=-28/14

x=-2

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