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5(2x+2)-3=2(x+5)
We move all terms to the left:
5(2x+2)-3-(2(x+5))=0
We multiply parentheses
10x-(2(x+5))+10-3=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
10x-(2x+10)+7=0
We get rid of parentheses
10x-2x-10+7=0
We add all the numbers together, and all the variables
8x-3=0
We move all terms containing x to the left, all other terms to the right
8x=3
x=3/8
x=3/8
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