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5(2x+1)+6x-13=3(3x-2)
We move all terms to the left:
5(2x+1)+6x-13-(3(3x-2))=0
We add all the numbers together, and all the variables
6x+5(2x+1)-(3(3x-2))-13=0
We multiply parentheses
6x+10x-(3(3x-2))+5-13=0
We calculate terms in parentheses: -(3(3x-2)), so:We add all the numbers together, and all the variables
3(3x-2)
We multiply parentheses
9x-6
Back to the equation:
-(9x-6)
16x-(9x-6)-8=0
We get rid of parentheses
16x-9x+6-8=0
We add all the numbers together, and all the variables
7x-2=0
We move all terms containing x to the left, all other terms to the right
7x=2
x=2/7
x=2/7
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