10(3c+8)+2c=-10(-3c+2)

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Solution for 10(3c+8)+2c=-10(-3c+2) equation: 



10(3c+8)+2c=-10(-3c+2)

We move all terms to the left:

10(3c+8)+2c-(-10(-3c+2))=0

We add all the numbers together, and all the variables

2c+10(3c+8)-(-10(-3c+2))=0

We multiply parentheses

2c+30c-(-10(-3c+2))+80=0



We calculate terms in parentheses: -(-10(-3c+2)), so:

-10(-3c+2)

We multiply parentheses

30c-20

Back to the equation:

-(30c-20)



We add all the numbers together, and all the variables

32c-(30c-20)+80=0

We get rid of parentheses

32c-30c+20+80=0

We add all the numbers together, and all the variables

2c+100=0

We move all terms containing c to the left, all other terms to the right

2c=-100

c=-100/2

c=-50

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