4(22v+92)=83v+53

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Solution for 4(22v+92)=83v+53 equation: 



4(22v+92)=83v+53

We move all terms to the left:

4(22v+92)-(83v+53)=0

We multiply parentheses

88v-(83v+53)+368=0

We get rid of parentheses

88v-83v-53+368=0

We add all the numbers together, and all the variables

5v+315=0

We move all terms containing v to the left, all other terms to the right

5v=-315

v=-315/5

v=-63

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