5(2x+1)+6x-13=(3x-2)

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Solution for 5(2x+1)+6x-13=(3x-2) equation: 



5(2x+1)+6x-13=(3x-2)

We move all terms to the left:

5(2x+1)+6x-13-((3x-2))=0

We add all the numbers together, and all the variables

6x+5(2x+1)-((3x-2))-13=0

We multiply parentheses

6x+10x-((3x-2))+5-13=0



We calculate terms in parentheses: -((3x-2)), so:

(3x-2)

We get rid of parentheses

3x-2

Back to the equation:

-(3x-2)



We add all the numbers together, and all the variables

16x-(3x-2)-8=0

We get rid of parentheses

16x-3x+2-8=0

We add all the numbers together, and all the variables

13x-6=0

We move all terms containing x to the left, all other terms to the right

13x=6

x=6/13

x=6/13

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