2x/(x+1)=2x-1/x

Solution for 2x/(x+1)=2x-1/x equation:

2x/(x+1)=2x-1/x

We move all terms to the left:

2x/(x+1)-(2x-1/x)=0


Domain of the equation: (x+1)!=0

We move all terms containing x to the left, all other terms to the right

x!=-1

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

2x/(x+1)-(+2x-1/x)=0

We get rid of parentheses

2x/(x+1)-2x+1/x=0

We calculate fractions


2x^2/(x^2+x)-2x+(1*(x+1))/(x^2+x)=0


We calculate terms in parentheses: +(1*(x+1))/(x^2+x), so:

1*(x+1))/(x^2+x

We add all the numbers together, and all the variables

x+1*(x+1))/(x^2

We multiply all the terms by the denominator


x*(x^2+1*(x+1))

Back to the equation:

+(x*(x^2+1*(x+1)))


We multiply all the terms by the denominator


2x^2-2x*(x^2+x)+((x*(x^2+1*(x+1))))*(x^2+x)=0


We calculate terms in parentheses: +((x*(x^2+1*(x+1))))*(x^2+x), so:

(x*(x^2+1*(x+1))))*(x^2+x

We add all the numbers together, and all the variables

x+(x*(x^2+1*(x+1))))*(x^2

Back to the equation:

+(x+(x*(x^2+1*(x+1))))*(x^2)


We multiply parentheses

2x^2-2x^3-2x^2+(x+(x*(x^2+1*(x+1))))*x^2=0

We do not support expression: x^3