5(2u+3)+u=-6(-2u-5)

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Solution for 5(2u+3)+u=-6(-2u-5) equation: 



5(2u+3)+u=-6(-2u-5)

We move all terms to the left:

5(2u+3)+u-(-6(-2u-5))=0

We add all the numbers together, and all the variables

u+5(2u+3)-(-6(-2u-5))=0

We multiply parentheses

u+10u-(-6(-2u-5))+15=0



We calculate terms in parentheses: -(-6(-2u-5)), so:

-6(-2u-5)

We multiply parentheses

12u+30

Back to the equation:

-(12u+30)



We add all the numbers together, and all the variables

11u-(12u+30)+15=0

We get rid of parentheses

11u-12u-30+15=0

We add all the numbers together, and all the variables

-1u-15=0

We move all terms containing u to the left, all other terms to the right

-u=15

u=15/-1

u=-15

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