5(2t+1)=35

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Solution for 5(2t+1)=35 equation: 



5(2t+1)=35

We move all terms to the left:

5(2t+1)-(35)=0

We multiply parentheses

10t+5-35=0

We add all the numbers together, and all the variables

10t-30=0

We move all terms containing t to the left, all other terms to the right

10t=30

t=30/10

t=3

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