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4+9x^2=72
We move all terms to the left:
4+9x^2-(72)=0
We add all the numbers together, and all the variables
9x^2-68=0
a = 9; b = 0; c = -68;
Δ = b2-4ac
Δ = 02-4·9·(-68)
Δ = 2448
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2448}=\sqrt{144*17}=\sqrt{144}*\sqrt{17}=12\sqrt{17}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{17}}{2*9}=\frac{0-12\sqrt{17}}{18} =-\frac{12\sqrt{17}}{18} =-\frac{2\sqrt{17}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{17}}{2*9}=\frac{0+12\sqrt{17}}{18} =\frac{12\sqrt{17}}{18} =\frac{2\sqrt{17}}{3} $
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