(8x-5)+(6-x)-20=2

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Solution for (8x-5)+(6-x)-20=2 equation: 



(8x-5)+(6-x)-20=2

We move all terms to the left:

(8x-5)+(6-x)-20-(2)=0

We add all the numbers together, and all the variables

(8x-5)+(-1x+6)-20-2=0

We add all the numbers together, and all the variables

(8x-5)+(-1x+6)-22=0

We get rid of parentheses

8x-1x-5+6-22=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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